**Help me with this calculus problem, I really need someone to help me figure out how to solve this problem?**

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*I have a practice test for my calculus final and I need to figure out how to do this stuff…. if anyone can do this problem and show the work for me to understand it, I would appreciate it…. it is: *

A load of grain is being dumped so that the grain forms a pile in the shape of a cone where the volume of the grain is given by V= (2Pie)/(9) x r^3 where r is the radius of the base of the pile. The radius of the base is changing at the rate of 4.8 ft/min at the moment the radius is 21.2 ft. How fast is the volume of the pile changing at that moment…. to the nearest tenth. Again, the equation is: 2 Pie divided by 9 times r^3 If you are smart, please help me

First, please use “pi” for 3.1416. That’s what they call the small Greek letter. If the volume is the relation given, V=V(r), so to get dV/dt, we use the “chain rule” dV/dr x dr/dt = dV/dt. Then dV/dt= (2 pi/9) 3r^2 dr/dt

Now all you do is substitute 4.8 ft/min for dr/dt, and 21.2 ft for r in the dV/dt equation and solve.

**Work It Out (Calculus Remix)**