Word Problems Springs Calculus Stretch

[mage lang="" source="flickr"]word problems springs calculus stretch[/mage]
calculus work word problem?

If a springs natural length is 1 foot and it requires 10 lbs of force to hold this spring stretched to a length 1.5 feet, how much work is done stretching this spring from 2 feet to 3?

spring force is F = k x, x= stretch…given F = 10 when x = 1/2 means k = 20. work = integral over [1,2] of 20 x means work = 10[2]^2 – 10[1]^1 = 30 ft pounds

Lec 6 | MIT 18.01 Single Variable Calculus, Fall 2007

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Category: Calculus Problems
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2 Responses
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