# Practice Calculus Problems With Answers

[mage lang="en|es|en" source="flickr"]practice calculus problems with answers[/mage]
Can anyone help me with the problems Pre-Calculus/Intro Calc?

Please explain your processes, I'm looking for the steps and answers, and I can practice and get right to the next time. any help is appreciated =] 2. Simplify: (x ^ 3-8) / (x-2) Apply this to the problems ———— 1.2, 3.7, 8: If f (x) = ((3.5) (2.4) (1.7)), h (x) = ((3.2), ( 4.3) (1.6)), g (x) = sqrt (x-3), k (x) = X ^ 2 + 5 1. (F + h) (1) 2. (Kg) (5) 3. (FOH) (3) 7. 1 / (f (x)) 8. (Kg) (x) —– 1. Evaluate (f (x + h) – f (x)) / (h) if f (x) = X ^ 2-2x —– Simplify: 3. e ^ (1 + lnx) 5. In e ^ 7 8. In 0.5 9. e ^ (3lnx) 14. (3 (n +1)!) / 5n! Given vectors v —— 5 =- 2i j, w = 3i +4 j, determine 3. length of w 4. unit vector w ——- Solve for x 0 when it is less than or equal to x is less than or equal to 2pi: 8. Sin 2x = sin x —- How I can find domain and range of graphics? THANK YOU! I did the best I could, and those were the ones I had to jump

(X ^ 3-8) / (x-2) [= (x-2) (x ^ 2 + x +4)] / (x-2) = X ^ 2 + x 4 1. (F + h) (1) = 7 +6 = 13 2. (Kg) (5) = 5 ^ 2 +5- sqrt (5.3) = 30-sqrt (2) 3. (FOH) (3) = f (2) = 4 7. 1 / (f (x)) = ((3.1 / 5), (2,1 / 4), (1,1 / 7)) 8. (Kg) (x) = (x ^ 2 +5) sqrt (x-3) (f (x + h) – f (x)) / (h) = ((x + h) ^ 2.2 (XH +)-x ^ 2 +2 x) / h = (X ^ 2 +2 xh + h ^ 2-2x-2h-x ^ 2 +2 x) / h = (h + 2xh ^ 2-2h) / h = 2x + h-2 3. e ^ (1 + lnx) ^ ee = (lnx) = e 5. In e ^ 7 = 7ln e = 7 8. 0.5 = ln2-9. e ^ (3lnx) = [e ^ (lnx)] ^ 3 = x ^ 3 14. (3 (n +1)!) / 5n! = 3 (n + 1) / 5 =- Given vectors v May 2i j, w = 3i +4 j, determined 3. | W | = sqrt (3 ^ 2 +4 ^ 2) = sqrt (9 +16) = sqrt (25) = 5 4. unit vector w = w / w | | = (3.5) i + (5.4) j 8. Sin 2x = sin x <=> 2 cos x = sinx sin x <= sin> x = 0 or cos x = 1 / 2 Answer: x = 0, pi, pi x = 2pi / 3, 5pi / 3 Email if you have more questions.

Calculus Problem Solver | Online Calculus Course

Category: Calculus Problems
You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.